找到以下两点之间的距离。
(1)A(3,7)和B(6,5)
(2)P(1,1)和Q(5,4)
(3)R(5,4)和S(-2,5)
(4)S(4,6)和T(7,7)
(5)N(2,6)和R(5,1)
两点之间的距离
=√(x 2 -x 1)2 +(y 2 -y 1)2
(1)此处x 1 = 3,y 1 = 7,x 2 = 6且y 2 = 5
A和B之间的距离=√(6-3)2 +(5-7)2
=√(3)2 +(-2)2
=√(9 + 4)
=√13个单位
(2)
此处x 1 = 1,y 1 = 1,x 2 = 5且y 2 = 4
P和Q之间的距离=√(5-1)2 +(4-1)2
=√4 2 + 3 2
=√16+ 9
=√25
= 5个单位
(3)
这里x 1 = 5,y 1 = 4,x 2 = -2和y 2 = 5
S和R之间的距离=√(-2-5)2 +(5-4)2
=√(-7)2 +1 2
=√(49 + 1)
=√50
=√(5 ⋅ 5 ⋅ 2)
=5√2单位
(4) 这里x 1 = 4,y 1 = 6,x 2 = 7和y 2 = 7
S和T之间的距离=√(7-4)2 +(7-6)2
=√3 2 1 2
=√(9 + 1)
=√10单位
(5)此处x 1 = 2,y 1 = 6,x 2 = 5且y 2 = 1
N和R之间的距离=√(5-2)2 +(1-6)2
=√3 2 +( - 5)²
=√(9 + 25)
=√34个单位
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